If the radius of a star is $R$ and it acts as a black body, what would be the temperature of the star, in which the rate of energy production is Q? ( $\sigma$ stands for Stefan's constant.)
Easy
Download our app for free and get started
(b)
$H=\sigma\left(4 \pi R^2\right) T^4$ $\left[H=\sigma e A T^4\right]$ for black body $e=1$
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
For a black body at temperature $727^{\circ} C$, its radiating power is $60\; watt$ and temperature of surrounding is $227^{\circ} C$. If temperature of black body is changed to $1227^{\circ} C$ then its radiating power will be ..... $watt$
Four rods of indentical cross-sectional area and made from the same metal form the sides of a square. The temperature of two diagonally opposite points are $\theta$ and $\sqrt2 \theta$ respectively in the teady state. Assuming that only heat conduction takes place, what will be the temperature difference between other two points ?
Three very large plates of same area are kept parallel and close to each other. They are considered as ideal black surfaces and have very high thermal conductivity. The first and third plates are maintained at temperatures $2T$ and $3T$ respectively. The temperature of the middle (i.e. second) plate under steady state condition is
At a certain temperature for given wave length, the ratio of emissive power of a body to emissive power of black body in same circumstances is known as
Energy is being emitted from the surface of a black body at $127\,^oC$ temperature at the rate of $1.0 \times {10^6}\,J/s - {m^2}$. Temperature of the black body at which the rate of energy emission is $16.0 \times {10^6}\,J/s - {m^2}$ will be ......... $^oC$
A black body radiates energy at the rate of $E$ $W/m^2$ at a high temperature $TK$ . When the temperature is reduced to $\frac{T}{2}K$, the radiant energy will be
A body cools from $60^{\circ} C$ to $40^{\circ} C$ in $6$ minutes. If, temperature of surroundings is $10^{\circ} C$. Then, after the next 6 minutes, its temperature will be $.........{ }^{\circ} C$.