MCQ
The relation between two specific heats of a gas is
- ✓${C_P} - {C_V} = \frac{R}{J}$
- B${C_V} - {C_P} = \frac{R}{J}$
- C${C_p} - {C_v} = J$
- D${C_v} - {C_p} = J$
✓
Answer
Correct option: A.
${C_P} - {C_V} = \frac{R}{J}$
a
$c_{p}-c_{V}=R$
$c_{p}-c_{V}=R$
This is the expression when $R$ is given in iuris of $J / mol / K$. when we convert into calories, the expression changes to -
$C_{p}-C_{v}=\frac{R}{T}$
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