If the velocity of sound in air is $350 m/s$. Then the fundamental frequency of an open organ pipe of length $50\,cm,$ will be ............... $\mathrm{Hz}$
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(a) Fundamental frequency of open pipe ${n_1} = \frac{v}{{2l}} = \frac{{350}}{{2 \times 0.5}} = 350$ $Hz$.
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