In a Carnot engine, when ${T_2} = {0^o}C$ and ${T_1} = {200^o}C,$ its efficiency is ${\eta _1}$ and when ${T_1} = 0{\,^o}C$ and ${T_2} = - 200{\,^o}C$, Its efficiency is ${\eta _2}$, then what is ${\eta _1}/{\eta _2}$
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The correct option ($s$) is (are)
$(A)$ $q_{A C}=\Delta U_{B C}$ and $W_{A B}=P_2\left(V_2-V_1\right)$ $(B)$ $W _{ BC }= P _2\left( V _2- V _1\right)$ and $q _{ BC }= H _{ AC }$ $(C)$ $\Delta H _{ CA }<\Delta U _{ CA }$ and $q _{ AC }=\Delta U _{ BC }$ $(D)$ $q_{B C}=\Delta H_{A C}$ and $\Delta H_{C A}>\Delta U_{C A}$
