In a circuit $5$ percent of total current passes through a galvanometer. If resistance of the galvanometer is $G$ then value of the shunt is
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(d) $\frac{{{i_g}}}{i} = \frac{S}{{G + S}}$
$ \Rightarrow $ $\frac{5}{{100}} = \frac{S}{{G + S}}$
$ \Rightarrow $ $S = \frac{G}{{19}}$
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