MCQ
In a experiment to measure the height of a bridge by dropping a stone into water underneath, if the error in the measurement of times is $0.1\;s$ at the end of $2\;s$, then the error in the estimation of the height of the bridge will be
  • A
    $0.49$
  • B
    $0.98$
  • $1.96$
  • D
    $2.12$

Answer

Correct option: C.
$1.96$
c
$s = {v_o}t + \frac{1}{2}a{t^2}$

$h = 0 + \frac{1}{2}(9.8){(2)^2} = 19.6\,m$

$\frac{{\Delta h}}{h} =  \pm 2\left( {\frac{{\Delta t}}{t}} \right)$ $(\because {a = g}$ constant$)$   

$ =  \pm 2\left( {\frac{{0.1}}{2}} \right) =  \pm 0.1\,$

$\therefore \Delta h=  \pm \frac{h}{{10}} =  \pm \frac{{19.6}}{{10}}=  \pm 1.96\,m$

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