In an experiment with photoelectric effect, the stopping potentia… - Vidyadip

MCQ

In an experiment with photoelectric effect, the stopping potential.

A
increases with increase in the wavelength of the incident light
B
increases with increase in the intensity of the incident light
✓
is $\left(\frac{1}{e}\right)$ times the maximum kinetic energy of the emitted photoelectrons
D
decreases with increase in the intensity of the incident light

✓

Answer

Correct option: C.

is $\left(\frac{1}{e}\right)$ times the maximum kinetic energy of the emitted photoelectrons

(C) is $\left(\frac{1}{e}\right)$ times the maximum kinetic energy of the emitted photoelectrons
Sol.
$\begin{aligned} \frac{ hC }{\lambda} & = W + eV _{ s } \\ \frac{ hC }{\lambda} & = W +\left( K _{\max }\right) \\ \therefore V _{ s } & =\frac{ K _{\max }}{ e }\end{aligned}$

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