In an $N P N$ transistor the collector current is $24 mA$. If $80 \%$ of electrons reach collector its base current in $m A$ is
A$36$
B$26$
C$16$
D$6$
[Kerala PMT 2004]
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D$6$
Given $i_c=\frac{80}{100} \times i_e \Rightarrow 24=\frac{80}{100} \times i_e \Rightarrow i_e=30 \mathrm{~mA}$
By using $i_e=i_b+i_c \Rightarrow i=30-24=6 \mathrm{~mA}$.
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For a transistor, the current amplification factor is $0.8.$ The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6 $m A$ is