In series LCR circuit, the plot of $I_{max}$ vs $\omega$ is shown in Fig. Find the bandwidth and mark in the figure.
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According top the given diagram,
Bandwidth $\Delta\omega=\omega_2-\omega_1$
where $\omega_1$ and $\omega_2$ correspond to frequencies at which magnitude of current is $\frac{1}{\sqrt{2}}$ times of maximum value.
i.e., $\text{I}_\text{rms}=\frac{\text{I}_\text{max}}{\sqrt{2}}=\frac{1\text{A}}{\sqrt{2}}\approx0.7\text{A}$
From the graph these frequencies are $\omega_1=0.8\frac{\text{rad}}{\text{s}}$ and $\omega_2=1.2\frac{\text{red}}{\text{s}}.$
Thus, bandwidth, $\Delta\omega=\omega_1-\omega_2=1.2-0.8=0.4\frac{\text{rad}}{\text{s}}.$
Bandwidth $\Delta\omega=\omega_2-\omega_1$
where $\omega_1$ and $\omega_2$ correspond to frequencies at which magnitude of current is $\frac{1}{\sqrt{2}}$ times of maximum value.
i.e., $\text{I}_\text{rms}=\frac{\text{I}_\text{max}}{\sqrt{2}}=\frac{1\text{A}}{\sqrt{2}}\approx0.7\text{A}$
From the graph these frequencies are $\omega_1=0.8\frac{\text{rad}}{\text{s}}$ and $\omega_2=1.2\frac{\text{red}}{\text{s}}.$
Thus, bandwidth, $\Delta\omega=\omega_1-\omega_2=1.2-0.8=0.4\frac{\text{rad}}{\text{s}}.$
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