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In a thermodynamics process, pressure of a fixed mass of a gas is changed in such a manner that the gas releases $20\,J$ of heat and $8\,J$ of work is done on the gas. If the initial internal energy of the gas was $30\,J$. The final internal energy will be...... $J$
An ideal gas, initially in state $\left( P _{12}, V _1, T _1\right)$ is expanded isobarically to $\left( P _{12}, V _2, T _2\right)$, then adiabatically $\left( P _{34}, V _3, T _3\right)$. It is then contracted isobarically to $\left( P _{34}, V _4, T _4\right)$ and finally adiabatically back to the initial state. The efficiency of this cycle is
A given mass of a gas expands from a state $A$ to the state $B$ by three paths $1, 2$ and $3$ as shown in $T-V$ indicator diagram. If $W_1, W_2$ and $W_3$ respectively be the work done by the gas along the three paths, then
$5.6$ liter of helium gas at $STP$ is adiabatically compressed to $0.7$ liter. Taking the initial temperature to be $T _1$, the work done in the process is
The latent heat of vaporization of water is $2240 \,J/gm$. If the work done in the process of vaporization of $1\, gm$ is $168\, J$, then increase in internal energy is .... $J$