In the circuit shown below the resistance of the galvanometer is $20\, \Omega$ . In which case of the following alternatives are the currents arranged strictly in the decreasing order
A$i, i_1, i_2, i_g$
B$i, i_2, i_1, i_g$
C$i, i_2, i_g, i_1$
D$i, i_1, i_g, i_2$
Medium
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B$i, i_2, i_1, i_g$
b (b) $i \propto \frac{1}{R}$
$P+Q>R+S$
$i=i_{1}+i_{2}$
$i>i_{2}>i_{1}>i_{g}$
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In the electric network shown, when no current flows through the $4\, \Omega $ resistor in the arm $EB$, the potential difference between the points $A$ and $D$ will be ............... $V$
A resistance $R = 12\, \Omega$ is connected across a source of emf as shown in the figure . Its $emf$ changes with time as shown in the graph . What is the heat developed in the resistance in the first four seconds ? ............. $J$
The charge flowing in a conductor varies with time as $Q = at -bt^2$. Then for current, which statement is incorrect.
$(A)$ decreases linearly with time
$(B)$ reaches a maximum and then decreases
$(C)$ fall to zero after time $t = a/2b$
$(D)$ changes at a rate $-2b$
Options :
The series combination of two batteries, both of the same emf $10 \mathrm{\;V},$ but different internal resistance of $20\; \Omega$ and $5\; \Omega,$ is connected to the parallel combination of two resistors $30\; \Omega$ and $\mathrm{R}\; \Omega .$ The voltage difference across the battery of internal resistance $20\; \Omega$ is zero, the value of $\mathrm{R}(\text { in } \Omega)$ is