In the circuit shown in figure reading of voltmeter is $V_1$ when only $S_1$ is closed, reading of voltmeter is $V_2$ when only $S_2$ is closed. The reading of voltmeter is $V_3$ when both $S_1$ and $S_2$ are closed then
A$V_2 > V_1 > V_3$
B$V_3 > V_2 > V_1$
C$V_3 > V_1 > V_2$
D$V_1 > V_2 > V_3$
Diffcult
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A$V_2 > V_1 > V_3$
a When $S_{1}$ is closed
$V_{1}=3 R \times \frac{E}{4 R}=\frac{3}{4} E$
$V_{2}=6 R \times \frac{E}{7 R}=\frac{6}{7} E$
$V_{3}=2 R \times \frac{E}{3 R}=\frac{2}{3} E$
$\mathrm{V}_{2}>\mathrm{V}_{1}>\mathrm{V}_{3}$
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