In the circuit shown in figure, the current drawn from the battery is $4\,A$. If $10 \,\Omega$ resistor is replaced by $20\,\Omega$ resistor, then current drawn from the circuit will be .............. $A$
A$1$
B$2$
C$3$
D$0$
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D$0$
d (d) Given circuit is a balanced Wheatstone bridge circuit. So there will be no change in equivalent resistance. Hence no further current will be drawn.
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