In the circuit shown in the figure, the total charge in $750\, \mu C$ and the voltage across capacitor $C _{2}$ is $20\, V$. Then the charge on capacitor $C _{2}$ is$....\mu C$
JEE MAIN 2020, Medium
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$q _{3}=20 \times 8=160 \mu C$
$\therefore q _{2}=750-160=590 \mu C$
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