In the figure, the distribution of energy density of the radiation emitted by a black body at a given temperature is shown. The possible temperature of the black body is ....... $K$
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(b) ${\lambda _m}T = b$ where $b = 2.89 \times {10^{ - 3}}mK$
==> $T = \frac{b}{{{\lambda _m}}} = \frac{{2.89 \times {{10}^{ - 3}}}}{{1.5 \times {{10}^{ - 6}}}}$$ \approx 2000K$
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