The radius of nucleus of silver (atomic number $=$ $47$) is $3.4 \times {10^{ - 14}}\,m$. The electric potential on the surface of nucleus is $(e = 1.6 \times {10^{ - 19}}\,C)$
  • A$1.99 \times {10^6}\,volt$
  • B$2.9 \times {10^6}\,volt$
  • C$4.99 \times {10^6}\,volt$
  • D$0.99 \times {10^6}\,volt$
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