a
At steady state no current flows through capacitor branch.
$\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}_{\mathrm{eq}}}\left[\frac{1}{\mathrm{R}_{\mathrm{eq}}}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3}\right]\left[\frac{1}{\mathrm{R}_{\mathrm{eq}}}=\frac{11}{6}\right]$
$I=6 \times \frac{11}{6}=11 \,A$
$\mathrm{Q}=\mathrm{CV}=0.5 \times 6=3\, \mu \mathrm{C}$