In the given figure the ratio of current in $8\,\Omega $ and $3\,\Omega $ will be
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$V=I_1 \times 12$ $V=I_2 \times 9$
$\frac{I_1}{I_2}=\frac{9}{12} \Rightarrow \frac{I_1}{I_2}=3 / 4$
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