MCQ
$\int_{}^{} {{{(\log x)}^2}\;dx = } $
- A$x{(\log x)^2} - 2x\log x - 2x + c$
- B$x{(\log x)^2} - 2x\log x - x + c$
- ✓$x{(\log x)^2} - 2x\log x + 2x + c$
- D$x{(\log x)^2} - 2x\log x + x + c$
then it reduces to $\int_{}^{} {{t^2}.\,{e^t}dt = {t^2}{e^t} - 2t{e^t} + 2{e^t} + c} $
$ = x{(\log x)^2} - 2x\log x + 2x + c$.
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