Question
$\int_{\,0}^{\,1} {\,|\,3{x^2} - 1\,|\,dx} $ का मान है
$ = [x - {x^3}]_0^{1/\sqrt 3 } + [{x^3} - x]_{1/\sqrt 3 }^1$
$ = \frac{1}{{\sqrt 3 }} - \frac{1}{{3\sqrt 3 }} + \frac{{ - 1}}{{3\sqrt 3 }} + \frac{1}{{\sqrt 3 }}$
$ = \frac{4}{{3\sqrt 3 }}$.
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