MCQ
$\int\limits_{ - 3}^1 {(2{{\left( {t + 1} \right)}^5} - 5{{\left( {t + 1} \right)}^3} + t + 3} {)dt}$ =
- ✓$8$
- B$5$
- C$20$
- D$\frac {15}{4}$
let $t+1=z$
$d t=d z$
$\int_{-2}^{2}\left(2 z^{5}-5 z^{3}+z+2\right) d t=8$
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