પ્રથમ પધ્ધતિ મોલારીટી $ = \,\,\frac{{weight \,\,of\,\,soule\,\, \times \,\,1000}}{{Molecular\,\,\,Weight\,\,of\,\,solute\,\, \times \,\,volume\,\,of\,\,solution\,\,\left( {mL} \right)}}$
$ = \,\,\frac{{0.4}}{{40\,\, \times \,\,40}}\,\, \times \,\,1000\,\, = \,\,0.25\,\,M$
અને $normality\,\, = \,\,\frac{{weight\,\,of\,\,solute}}{{Equivalent\,\,weight\,\,of\,dolute\,\, \times \,\,volume\,\,of\,\,solution\,\,\left( {ml.} \right)}}\,\,$ $ \times \,\,1000$
$NaOH$ નો તુલ્યભાર $=\,40$
તેથી $, N\,\, = \,\,\frac{{0.4}}{{40\,\, \times \,\,40}}\,\, \times \,\,1000\,\, = \,\,0.25\,$
દ્રિતય પધ્ધતિ $N\,\, = \,\,M\,\, \times \,\,n $
અહી $n\,\, = \,\,1,\,\,\,\,N\,\, = \,\,M,\,\,\,N\,\, = \,\,0.25$
[અહી આપેલ : પાણીનો મોલલ અચળાંક= $1.85 \,K \,kg \,mol ^{-1}$ શુદ્ધ પાણીનો ઠંડક $\left.=0^{\circ} C \right]$
(યુરિયાનો અણુભાર $= 60\, g\, mol^{-1}$)