જો $A = {\log _2}{\log _2}{\log _4}256 + 2{\log _{\sqrt 2 \,}}\,2$ તો $A = . . . .$
  • A$2$
  • B$3$
  • C$5$
  • D$7$
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c
(c) \(A = {\log _2}{\log _2}{\log _4}256\) + \(2{\log _2}_{^{1/2}}\,2\)

\( = {\log _2}{\log _2}{\log _4}{4^4} + 2 \times {1 \over {(1/2)}}{\log _2}2\)

\( = {\log _2}{\log _2}4 + 4 = {\log _2}{\log _2}{2^2} + 4\)

\( = {\log _2}2 + 4 = 1 + 4 = 5\).

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