MCQ
જો $\frac{\mathrm{d}}{\mathrm{dx}} f(\mathrm{x})=\mathrm{g}(\mathrm{x})$ તો $\frac{\mathrm{d}}{\mathrm{dx}} f(a \mathrm{x}+\mathrm{b})=\ldots \ldots \ldots$
- A$g (a x + b )$
- B$a g(x)$
- ✓$a g(a x+b)$
- D$\operatorname{bg}(a x+b)$
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