${\text{5}}{{\text{a}}^{\text{2}}}{\text{ + 6a}}{\text{.b - 8}}{{\text{b}}^{\text{2}}}{\text{ = 0}}$
${\text{6a}}{\text{.b = 3, (}}\because \,\,{\text{ }}{{\text{a}}^{\text{2}}}{\text{ = 1, }}{{\text{b}}^{\text{2}}}{\text{ = 1)}}$
$\therefore \,\,\,a.b\,\, = \,\,\frac{1}{2}\,$
$|a|\,\,|b|\,\,cos\theta \, = \,\,\,\frac{1}{2}\,\,\,\,\,\,$
$\therefore \,\,\,\cos \theta \,\, = \,\frac{1}{2}\,,\,\,\,\,\,$
$\therefore \,\,\theta \,\, = \,\,{60^ \circ }$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
|
$X$ |
$1$ |
$2$ |
$3$ |
$4$ |
$5$ |
$6$ |
$7$ |
$8$ |
|
$P(X)$ |
$0.15$ |
$0.23$ |
$0.12$ |
$0.10$ |
$0.20$ |
$0.08$ |
$0.07$ |
$0.05$ |