MCQ
જો $y = {({x^2} - 1)^m}$, તો $y$ નું ${(2m)^{th}}$ મું વિકલન મેળવો.
- A$m$
- ✓$(2m)!$
- C$2m$
- D$m!$
$y = {({x^2} - 1)^m}{ = ^m}{C_o}{x^{2m}}{ + ^m}{C_1}{x^{2m - 2}}( - 1) + .......$
So on differentiating all the terms except first reduces to zero, therefore
$\frac{{{d^{2m}}y}}{{d{x^{2m}}}}{ = ^m}{C_0}2m{\rm{ }}(2m - 1){\rm{ }}(2m - 2)....1 = (2m)!$.
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