$\Rightarrow \quad$ Mass of ${Br}=\frac{0.2397}{188} \times 80\, {~g}$

therefore $\%$ Br in the organic compound

$=\frac{W_{\text {Br }}}{W_{T}} \times 100$

$=\frac{0.2397 \times 80}{188 \times 0.15} \times 100=0.85 \times 80$

$=68$

$\Rightarrow$ Nearest integer is $'68^{\prime}$