Kinetic energy of an electron accelerated in a potential difference of $100\, V$ is
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(a) By using $KE = QV$ $==>$ $KE = 1.6 × 10^{-19} × 100$
$= 1.6 × 10^{-17} \,J$
$= 1.6 × 10^{-17} \,J$
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