$q _{ y }=-\sigma 4 \pi b ^2$
$q _{ z }=\sigma 4 \pi c ^2$
Potential $x =$ potential $z$
$V _{ x }= V _{ z }$
$\frac{ q _{ x }}{4 \pi \varepsilon_0 a }+\frac{ q _{ y }}{4 \pi \varepsilon_0 b }+\frac{ q _{ z }}{4 \pi \varepsilon_0 c }=\frac{ q _{ x }}{4 \pi \varepsilon_0 c }+\frac{ q _{ y }}{4 \pi \varepsilon_0 c }+\frac{ q _{ z }}{4 \pi \varepsilon_0 c }$
$\frac{\sigma 4 \pi a ^2}{ a }-\frac{\sigma 4 \pi b ^2}{ b }+\frac{\sigma 4 \pi c ^2}{ c }=\frac{4 \pi \sigma\left[ a ^2- b ^2+ c ^2\right]}{ c }$
$c ( a - b + c )= a ^2- b ^2+ c ^2$
$c ( a - b )= a ^2- b ^2$
$c = a + b$
$c =5\,cm$
$A$. the charge stored in it, increases.
$B$. the energy stored in it, decreases.
$C$. its capacitance increases.
$D$. the ratio of charge to its potential remains the same.
$E$. the product of charge and voltage increases.
Choose the most appropriate answer from the options given below:



