\(\therefore \frac{d x}{\sqrt{x}}=\alpha d t\)
સંકલન લેતા \(\int \frac{d x}{\sqrt{x}}=\alpha \int d t\)
\(\therefore 2 x^{1 / 2}=\alpha t\)
\(\therefore x \propto t^{2}\)
$\left[ g =10 \,ms ^{-2}\right.$ લો.$]$
$\begin{array}{|c|c|c|c|c|} \hline t( s ) & 0 & 1 & 2 & 3 \\ \hline x ( m ) & -2 & 0 & 6 & 16 \\ \hline \end{array} $