કોષને ધ્યાનમાં લો

$Pt _{( s )}\left| H _2( g , 1\,atm )\right| H ^{+}( aq , 1 M )|| Fe ^{3+}( aq ), Fe ^{2+}( aq ) \mid Pt ( s )$

$298\,K$ પર જયારે કોષ નો પોટેન્શિયલ $0.712\,V$ હોય તો $\left[ Fe ^{2+}\right] /\left[ Fe ^{3+}\right]$ નો ગુણોત્તર $.......$ છે.

આપેલ:$Fe ^{3+}+ e ^{-}= Fe ^{2+}, E ^{\circ} Fe ^{3+}, Fe ^{2+} \mid Pt =0.771$

$\frac{2.303 RT }{ F }=0.06\,V$

Question

કોષને ધ્યાનમાં લો

$Pt _{( s )}\left| H _2( g , 1\,atm )\right| H ^{+}( aq , 1 M )|| Fe ^{3+}( aq ), Fe ^{2+}( aq ) \mid Pt ( s )$

$298\,K$ પર જયારે કોષ નો પોટેન્શિયલ $0.712\,V$ હોય તો $\left[ Fe ^{2+}\right] /\left[ Fe ^{3+}\right]$ નો ગુણોત્તર $.......$ છે.

આપેલ:$Fe ^{3+}+ e ^{-}= Fe ^{2+}, E ^{\circ} Fe ^{3+}, Fe ^{2+} \mid Pt =0.771$

$\frac{2.303 RT }{ F }=0.06\,V$

JEE MAIN 2023, Diffcult

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Solution

b
$Pt _{( s )}\left| H _2( g , 1 atm )\right| H ^{+}( aq , 1 M ) \| Fe ^{3+}( aq ), Fe ^{2+}( aq )| Pt |( s )$

$\text { at anode } H _2 \longrightarrow 2 H ^{+}+2 e ^{-}$

$\text {At cathode } Fe _{ aq }^{3+}+ e ^{-} \longrightarrow Fe _{ aq }^{2+}$

$E ^{\circ}= E _{ H _2 / H ^{+}}^{\circ}+ E _{ Fe ^{3+} Fe ^{2+}}^{\circ}=0 \cdot 771\,V$

$E = E ^{\circ}-\frac{0 \cdot 06}{1} \log \frac{ Fe ^{2+}}{ Fe ^{3+}}$

$0 \cdot 712=(0+0 \cdot 771)-\frac{0 \cdot 06}{1} \log \frac{ Fe ^{2+}}{ Fe ^{3+}}$

$\log \frac{ Fe ^{2+}}{ Fe ^{3+}}=\frac{0 \cdot 059}{0 \cdot 06} \approx 1$

$\frac{ Fe ^{2+}}{ Fe ^{3+}}=10$

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