$(i)$ $Zn| Zn^{2+} {(1\,M)}|| Cu^{2+}{(0.1\,M)}| Cu$
$(ii)$ $Zn| Zn^{2+} {(1\,M)}|| Cu^{2+}(1\,M) |Cu $
$(iii)$ $Zn| Zn^{2+} {(0.1\,M)}|| Cu^{2+}{(1\,M)}| Cu$
જેમ $log [Zn^{2+}]/[Cu^{2+}]$ નું મૂલ્ય જેમ વધુ તેમ $E$ નું મૂલ્ય ઓછું.
${\text{(i)}}\,\,{\text{log }}\left[ {\frac{{{\text{Z}}{{\text{n}}^{{\text{2 + }}}}}}{{{\text{C}}{{\text{u}}^{{\text{2 + }}}}}}} \right] = 10;\,\,\,\,\,\,(ii)\,\,{\text{log }}\left[ {\frac{{{\text{Z}}{{\text{n}}^{{\text{2 + }}}}}}{{{\text{C}}{{\text{u}}^{{\text{2 + }}}}}}} \right]$$ = 1;\,\,$
$\,(iii)\,\,{\text{log }}\left[ {\frac{{{\text{Z}}{{\text{n}}^{{\text{2 + }}}}}}{{{\text{C}}{{\text{u}}^{{\text{2 + }}}}}}} \right] = 0.1\,\,\,\,\,\,\,\therefore \,\,\,\,{E_3} > {E_2} > {E_1}$
$\lambda_{\mathrm{m}\left(\mathrm{H}_{2} \mathrm{SO}_{4}\right)}^{0}=\mathrm{x} \;\mathrm{S}\; \mathrm{cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}\left(\mathrm{K}_{2} \mathrm{SO}_{4}\right)}^{0}=\mathrm{y} \;\mathrm{S\;cm}^{2} \mathrm{mol}^{-1}$
$\lambda_{\mathrm{m}(\mathrm{CH_3} \mathrm{COOK})}^{0}=\mathrm{z}\; \mathrm{S\;cm}^{2} \mathrm{mol}^{-1}$
$\mathrm{CH}_{3} \mathrm{COOH}$ માટે $\lambda_{\mathrm{m}}^{0}\left(\mathrm{in}\; \mathrm{S} \;\mathrm{cm}^{2} \mathrm{mol}^{-1}\right)$ શું હશે ?
$Zn | ZnSO_4 \,(0.01\, M) | | CuSO_4\,(1.0\, M) | Cu$
જ્યારે $ZnSO_4$ ની સાંદ્રતા $1.0\,M$ ત્યારેજ $CuSO_4$ ની સાંદ્રતા $0.01\,M$ છે $emf$$E_2$ માં બદલાય છે $E_1$ અને $E_2$ વચ્ચેનો સંબંધ શું હશે ?