where \(T = \) weight of part of rope hanging below the point under consideration
\( = \left( {\frac{M}{L}} \right)xg\)
==> \(v = \sqrt {\frac{{\left( {\frac{M}{L}} \right)xg}}{{\left( {\frac{M}{L}} \right)}}} = \sqrt {xg} \).
$y=\left(10 \cos \pi x \sin \frac{2 \pi t }{ T }\right) cm$
$x=\frac{4}{3} cm$ આગળ રહેલા કણનો કંપવિસ્તાર.....$cm$ હશે