MCQ
$\left(sec \theta + tan \theta - 1\right) \left(sec \theta - tan \theta + 1\right) = .......$
- A$2 sec^2 \theta$
- B$\frac{1}{2} \left(sec^2 \theta + tan^2 \theta\right)$
- C$2$
- ✓$2 tan \theta$
$\left(sec \theta + tan\theta - 1\right) \left(sec \theta - tan \theta + 1\right)$
$= \left[sec \theta + \left(tan \theta - 1\right)\right] \left[sec \theta- \left(tan \theta - 1\right)\right]$
$= sec^2 \theta - \left(tan \theta - 1\right)^2$
$= sec^2 \theta - tan^2 \theta + 2 tan \theta - 1$
$= 1+ 2 tan \theta - 1$
$= 2 tan \theta $
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