and side of image square \(=\ell^{\prime}\)
From question, \(\frac{\ell^{\prime 2}}{{\ell}^2 }=9\)
or \(\quad \frac{\ell^{\prime}}{\ell}=3\)
i.e., magnificationm \(=3\)
\(\mathrm{u}=-40 \mathrm{cm}\)
\(\mathrm{v}=3 \times 40=120\, \mathrm{cm}\)
\(f=?\)
From formula, \(\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\)
\(\frac{1}{120}-\frac{1}{-40}=\frac{1}{f}\)
or, \(\frac{1}{f}=\frac{1}{120}+\frac{1}{40}=\frac{1+3}{120} \therefore f=30\, \mathrm{cm}\)
$\left( c =3 \times 10^{8} ms ^{-1}\right)$