Let $A$ and $B$ the two gases and given : $\frac{{{T_A}}}{{{M_A}}} = 4.\frac{{{T_B}}}{{{M_B}}};$ where $T$ is the temperature and M is molecular mass. If ${C_A}$ and ${C_B}$ are the $r.m.s. $ speed, then the ratio $\frac{{{C_A}}}{{{C_B}}}$ will be equal to
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