........ $N$ the maximum force for which both the block will move with same acceleration.
Medium
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Pseudo force on 4 kg block $=\mathrm{ma}$
$\therefore \mathrm{ma}=\mu \mathrm{mg} \Rightarrow \mathrm{a}=0.4 \times 10=4 \mathrm{m} / \mathrm{s}^{2}$
as both the blocks will move with same
acc$”a”$
${F=(4+8) a}$
${=12 \times 4=48 \mathrm{N}}$
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