Let, oxidation number of \(F e=x\)
Oxidation number of \(C N=-1\)
Oxidation number of \(N O S=-1\)
Therefore, \(x+(-1) \times 5+1(-1)=-4\)
\(x-5-1=-4\)
\(x=+2\)
| સૂચી $-I$ | સૂચી $-II$ |
| $A.$ $\mathrm{K}_2\left[\mathrm{Ni}(\mathrm{CN})_4\right]$ | $I$ $\mathrm{sp}^3$ |
| $B.$ $\left[\mathrm{Ni}(\mathrm{CO})_4\right]$ | $II$ $\mathrm{sp}^3 \mathrm{~d}^2$ |
| $C.$ $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3$ | $III$ $\mathrm{dsp}^2$ |
| $D.$ $\mathrm{Na}_3\left[\mathrm{CoF}_6\right]$ | $IV$ $\mathrm{d}^2 \mathrm{sp}^3$ |
નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો:
$(I)\, [Ni(CN)_4]^{2-}\,\,\,(II)\, [NiCl_4]^{2-}\,\,\,(III)\,Ni(CO_4)\,\,\,$
$(IV)\, [Ni(H_2O)_6 ]^{2+}$