So \(\Lambda_{{m} {CH}_{3} {COOH}}^{\infty}=\Lambda_{{m}\left({H}^{+}\right)}^{\infty}+\Lambda_{{m} {CH}_{3} {COO}^{-}}^{\infty}\)

\(=349.8+40.9\)

\(=390.7\, {Scm}^{2} / {mole}\)

\(\Lambda_{{m} {KCl}}^{\infty}= \Lambda_{{m}\left({K}^{*}\right)}^{\infty}+\Lambda_{{m}({Cl}^{-})}^{\infty})\)

\(= 73.5+76.3\)

\(= 149.3\, {Scm}^{2} / {mole}\)

So statement\(-I\) is wrong or False.

As the concentration decreases, the dilution increases which increases the degree of dissociation, thus increasing the no. of ions, which increases the molar conductance.

So statement\(-II\) is false.