Here, oxidation state of \(F e=+3\)
Electronic configuration of \(F e\) (ground state) \(=[A r] 3 d^{6} 4 s^{2}\)
Electronic configuration of \(F e\) (excited state) \(=[A r] 3 d^{5} 4 s^{0}\)
Number of unpaired electrons \(=5\)
(ii) \(\left[F e(C N)_{6}\right]^{4-}\)
Here, oxidation state of \(F e=+2\)
Electronic configuration of \(F e\) (ground state) \(=[A r] 3 d^{6} 4 s^{2}\)
Electronic configuration of \(F e\) (excited state) \(=[A r] 3 d^{6} 4 s^{0}\)
Number of unpaired electrons \(=4\)
(iii) \(\left[\operatorname{Cr}\left(H_{2} O\right)_{6}\right]^{3+}\)
Here, oxidation state of \(C r=+3\)
Electronic configuration of \(C r^{3+}=[A r] 3 d^{3} 4 s^{0}\)
Number of unpaired electrons \(=3\)
(iv) \(\left[ Cu \left( H _{2} O \right)_{6}\right]^{2+}\)
Here, oxidation state of \(C u=+2\)
Electronic configuration of \(C u^{2+}=[A r] 3 d^{9} 4 s^{0}\)
Number of unpaired electrons \(=1\)
A number of unpaired electrons present is directly proportional to a paramagnetic character.
So, \(\left[ Fe ( CN )_{6}\right]^{3-}\) has maximum paramagnetic character.
$(I)\,[Cr(NO_3)_3(NH_3)_3]$ $(II)\, K_3[Fe(C_2O_4)_3]$ $(III)\,[CoCl_2(en)_2]^+$ $(IV)\, [CoBrCl(ox)_2]^{3-}$
ટ્રાન્સ$-[Co(en)\left._{2} Cl _{2}\right]^{+}( A )$ અને સિસ$-[Co(en)$ $\left._{2} Cl _{2}\right]^{+}$ $(B).$
તેમના વિશે સાચા વિધાનો ક્યા છે: