Here, oxidation state of \(F e=+3\)
Electronic configuration of \(F e\) (ground state) \(=[A r] 3 d^{6} 4 s^{2}\)
Electronic configuration of \(F e\) (excited state) \(=[A r] 3 d^{5} 4 s^{0}\)
Number of unpaired electrons \(=5\)
(ii) \(\left[F e(C N)_{6}\right]^{4-}\)
Here, oxidation state of \(F e=+2\)
Electronic configuration of \(F e\) (ground state) \(=[A r] 3 d^{6} 4 s^{2}\)
Electronic configuration of \(F e\) (excited state) \(=[A r] 3 d^{6} 4 s^{0}\)
Number of unpaired electrons \(=4\)
(iii) \(\left[\operatorname{Cr}\left(H_{2} O\right)_{6}\right]^{3+}\)
Here, oxidation state of \(C r=+3\)
Electronic configuration of \(C r^{3+}=[A r] 3 d^{3} 4 s^{0}\)
Number of unpaired electrons \(=3\)
(iv) \(\left[ Cu \left( H _{2} O \right)_{6}\right]^{2+}\)
Here, oxidation state of \(C u=+2\)
Electronic configuration of \(C u^{2+}=[A r] 3 d^{9} 4 s^{0}\)
Number of unpaired electrons \(=1\)
A number of unpaired electrons present is directly proportional to a paramagnetic character.
So, \(\left[ Fe ( CN )_{6}\right]^{3-}\) has maximum paramagnetic character.
| સૂચી $- I$ | સૂચી $- II$ |
| $(A)$ $\left[ PtCl _{4}\right]^{2-}$ | $(I)$ $sp ^{3} d$ |
| $(B)$ $BrF _{5}$ | $(II)$ $d ^{2} sp ^{3}$ |
| $(C)$ $PCl _{5}$ | $(III)$ $dsp ^{2}$ |
| $(D)$ $\left[ Co \left( NH _{3}\right)_{6}\right]^{3+}$ | $(IV)$ $sp ^{3} d ^{2}$ |
નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.
વિધાન ($I$) : $\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$ દ્રાવણ લીલા રંગનું છે.
વિધાન ($II$) : $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ નું દ્રાવણુ રંગવિહીન છે.
ઉપરના વિધાનોના સંદર્ભમાં, નીચે આપેલા વિકલ્પોમાંથી સૌથી બંધબેસતો જવાબ પસંદ કરો.

$(A)$ $\left. Na _{4}\left[ Fe ( CN )_{5} NOS \right)\right]$
$(B)$ $Na _{4}\left[ FeO _{4}\right]$
$(C)$ $\left[ Fe _{2}( CO )_{9}\right]$