\(\begin{array}{*{20}{c}} {C{H_3} - CH - CH = C{H_2}} \\ {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}\xrightarrow{{{O_3}/{H_2}{O_2}}}\)
\(\begin{array}{*{20}{c}} {C{H_3} - CH - COOH + HCOOH} \\ {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}\)
$PhCHO + Ph \cdot CHO \xrightarrow[in\,\,{{D}_{2}}O]{NaOD} A + \begin{matrix} O \\ || \\ Ph-C-{{O}^{-}} \\ \end{matrix}$$\left( Ph\right.$ is $\left.- C _{6} H _{5}\right)$
નીપજ $(C)$ શું હશે ?
સૂચી $-I$ | સૂચી $-II$ | ||
$(a)$ |
$\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - Cl \to R - CHO} \end{array}$ |
$(i)$ |
$Br _{2} / NaOH$ |
$(b)$ | $\begin{array}{*{20}{c}} {R - C{H_2} - COOH \to R - CH - COOH} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl} \end{array}$ |
$(ii)$ | $H _{2} / Pd - BaSO _{4}$ |
$(c)$ | $\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - N{H_2} \to R - N{H_2}} \end{array}$ |
$(iii)$ | $Zn ( Hg ) /$ સાંદ્ર. $HCl$ |
$(d)$ | $\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - C{H_3} \to R - C{H_2} - C{H_3}} \end{array}$ |
$(iv)$ | $Cl _{2}$ / લાલ $P , H _{2} O$ |
નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.
$(a)$ $PhCOOH$
$(B)$ $o-NO_2C_6H_4COOH$
$(C)$ $p-NO_2C_6H_4COOH$
$(D)$ $m-NO_2C_6H_4COOH$