$Ni$ના ચાર સંકીર્ણ છે. સંકીર્ણ (es) પસંદ કરો જે ચુંબકીય ક્ષેત્ર દ્વારા આકર્ષિત થશે :

$(I)\, [Ni(CN)_4]^{2-}\,\,\,(II)\, [NiCl_4]^{2-}\,\,\,(III)\,Ni(CO_4)\,\,\,$

$(IV)\, [Ni(H_2O)_6 ]^{2+}$

Question

$Ni$ના ચાર સંકીર્ણ છે. સંકીર્ણ (es) પસંદ કરો જે ચુંબકીય ક્ષેત્ર દ્વારા આકર્ષિત થશે :

$(I)\, [Ni(CN)_4]^{2-}\,\,\,(II)\, [NiCl_4]^{2-}\,\,\,(III)\,Ni(CO_4)\,\,\,$

$(IV)\, [Ni(H_2O)_6 ]^{2+}$

Aમાત્ર $I$
Bમાત્ર $IV$
C$II, III$ અને $IV$
D$II$ અને $IV$

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Solution

d
Paramagnetic complexes will be attracted by the magnetic field.

$\left[ NiCl _4\right]^{2-}$ and $\left[ Ni ^2\left( H _2 O \right)_6\right]^{2+}$ contain 2 unpaired electrons each. Thus they are paramagnetic and will be attracted by the magnetic field.

In $\left[ Ni ( CN )_4\right]^{2-}$ and $\left[ Ni ( CO )_4\right]$, all the electrons are paired. Hence, they are diamagnetic substances and are not attracted by the magnetic field.

કૉલમ$-I$	કૉલમ$-II$
$(a)\;Co^{+3}$	$(i)\;\sqrt{8}\; B.M.$
$(b)\;Cr^{+3}$	$(ii)\;\sqrt{35}\; B.M.$
$(c)\;Fe^{+3}$	$(iii)\;\sqrt{3}\; B.M.$
$(d)\;Ni^{+2}$	$(iv)\;\sqrt{24}\; B.M.$
	$(v)\;\sqrt{15}\; B.M.$

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