Initial energy of gas = Final energy
Let K.E. of each molecule initially be \(E_0\)
\(\therefore\) Total kinetic energy \(=E_0 \times n\)
Let final kinetic energy of each molecule be \(E_f\)
\(E_0 \times n=E_f \times 2 n\)
\(E_f=\frac{E_0}{2}\)
Since temperature is the average kinetic energy of molecules.
\(T_0=K E_0 \quad T_f=\frac{K E_0}{2}\)
\(\therefore\) Temperature becomes \(T_f=\frac{T_0}{2}\)
$\left(\right.\left.{k}_{{B}}=1.38 \times 10^{-23} \, {J} / {K}\right)$