$\left(\right.\left.{k}_{{B}}=1.38 \times 10^{-23} \, {J} / {K}\right)$
Translation K.E. of \({N}_{2}={KE}\). of electron
\(\frac{3}{2} {kT}={eV}\)
\(\frac{3}{2} \times 1.38 \times 10^{-23} {T}=1.6 \times 10^{-19} \times 0.1\)
\(\Rightarrow {T}=773 {k}\)
\({T}=773-273=500^{\circ} {C}\)
[વાયુ અચળાંક $8.3\, {J} {mol}^{-1} {K}^{-1}$ લો]