$NO(g) + Br_2 (g) \rightleftharpoons NOBr_2 (g)$
$NOBr_2(g)+ NO(g)\longrightarrow 2NOBr(g)$
જો બીજો તબક્કો ધીમો તબક્કો હોય, તો $NO(g)$ ની સાપેક્ષે પ્રક્રિયા ક્રમ ........ થશે.
\((ii) \quad \operatorname{NOBr}_{2}(g)+N O(g) \longrightarrow 2 N O B r\,(g)\)
Rate law equation \(=k\left[N O B r_{2}\right][N O]\)
But \(N O B r_{2}\) is intermediate and
must not appear in the rate law equation
from \(1^{st}\) step \(K_{C}=\frac{\left[N O B r_{2}\right]}{[N O]\left[B r_{2}\right]}\)
\(\therefore \quad\left[N O B r_{2}\right]=K_{C}[N O]\left[B r_{2}\right]\)
Rate law equation \(=k . K_{C}[N O]^{2}\left[B r_{2}\right]\)
hence order of reaction is \(2\) wr.t. \(N O .\)
$\left( {{\rm{R}} = 8.3\;{\rm{Jmo}}{{\rm{l}}^{ - 1}}{{\rm{K}}^{ - 1}},\ln \left( {\frac{2}{3}} \right) = 0.4,\left. {{e^{ - 3}} = 4.0} \right)} \right.$