==> \(\frac{{{v_1}}}{{{v_2}}} = \frac{8}{1} = \frac{{{m_2}}}{{{m_1}}}\)…… \((i) \)
Also from \(r \propto {A^{1/3}}\)
==> \(\frac{{{r_1}}}{{{r_2}}} = {\left( {\frac{{{A_1}}}{{{A_2}}}} \right)^{1/3}} = {\left( {\frac{1}{8}} \right)^{1/3}} = \frac{1}{2}\).