c
Ideal gas equation is given by $:$
$\mathrm{PV}=\mathrm{nRT}$ $...(i)$
For oxygen : $\mathrm{p}=1$ atm; $\mathrm{V}=1 \mathrm{L} ; \mathrm{n}=n_{O_{2}}$
Therefore, eqn. $(i)$ becomes,
$\therefore 1 \times 1=n_{O_{2}} R T$ or $n_{O_{2}}=\frac{1}{R T}$
For nitrogen : $\mathrm{p}=0.5$ atm; $\mathrm{V}=2 \mathrm{L} ; \mathrm{n}=2_{N_{2}}$
$\therefore 0.5 \times 2=n_{N_{2}} R T \quad$ or $n_{N_{2}}=\frac{1}{R T}$
For mixture of gas:
$P_{\operatorname{mix}} \cdot V_{\operatorname{mix}}=n_{\operatorname{mix}} R T$
Here, $\mathrm{n}_{\operatorname{mix}}=n_{O_{2}}+n_{N_{2}}$
$\therefore \frac{P_{m i x} J_{m i x}}{R T}=\frac{1}{R T}+\frac{1}{R T}$
$\therefore V_{\operatorname{mix}}=1 L ; P_{\operatorname{mix}}=2 a t m$