| Column $I$ | Column $II$ |
| $(A)$ Process $A \rightarrow B$ | $(p)$ Internal energy decreases. |
| $(B)$ Process $B \rightarrow C$ | $(q)$ Internal energy increases. |
| $(C)$ Process $C \rightarrow D$ | $(r)$ Heat is lost. |
| $(D)$ Process $D \rightarrow A$ | $(s)$ Heat is gained. |
| $(t)$ Work is done on the gas. |

W is $- Ve ; \Delta U$ is $- Ve ; \Delta Q$ is - Ve
for $(B)$ : $C$ is Isochoric
$W = O ; \Delta U$ is $- Ve ; \Delta Q$ is - Ve
for $(C)$ : $CD$ is Isobaric expansion
$W$ is $+V e ; \Delta U$ is $+V e ; \Delta Q$ is $+V e$
for $(D)$ : $DA$ is Isothermal
W is $- Ve ; \Delta U=0 ; \Delta Q$ is - Ve
The correct option ($s$) is (are)
$(A)$ $q_{A C}=\Delta U_{B C}$ and $W_{A B}=P_2\left(V_2-V_1\right)$ $(B)$ $W _{ BC }= P _2\left( V _2- V _1\right)$ and $q _{ BC }= H _{ AC }$ $(C)$ $\Delta H _{ CA }<\Delta U _{ CA }$ and $q _{ AC }=\Delta U _{ BC }$ $(D)$ $q_{B C}=\Delta H_{A C}$ and $\Delta H_{C A}>\Delta U_{C A}$