A source supplies heat to a system at the rate of $1000 \,W$. If the system performs work at a rate of $200\,W$. The rate at which internal energy of the system increases $.......\,W$
JEE MAIN 2023, Easy
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$dQ=dU+dw$
$\frac{\mathrm{dU}}{\mathrm{dt}}=\frac{\mathrm{dQ}}{\mathrm{dt}}-\frac{\mathrm{dw}}{\mathrm{dt}}$
$\frac{\mathrm{dU}}{\mathrm{dt}}=1000-200=800 \mathrm{~W}$
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