Let depth of water in cylinder be \(x\)
So velocity \((v)\) of efflux \(=\sqrt{2 g x}\)
Time taken \((t)\) by water to travel vertical distance of \(H\)
\(=\sqrt{\frac{2 H}{g}}\)
\(\Rightarrow \text { Range }=v \times t\)
\(R=\sqrt{2 g x} \times \sqrt{\frac{2 H}{g}}\)
Solving this we get
\(\frac{R^2}{4 H}=x\)
(પ્રવાહી એકબીજામાં મિશ્ર થતાં નથી)